![SOLVED: Let A = -4 1 3 33 2 Find the dimensions of the kernel and image (range) of T, where T(z) = Ax. dim(Ker(T)) = dim(Im(T)) SOLVED: Let A = -4 1 3 33 2 Find the dimensions of the kernel and image (range) of T, where T(z) = Ax. dim(Ker(T)) = dim(Im(T))](https://cdn.numerade.com/ask_images/530512d470334439ac1b1838ca478adb.jpg)
SOLVED: Let A = -4 1 3 33 2 Find the dimensions of the kernel and image (range) of T, where T(z) = Ax. dim(Ker(T)) = dim(Im(T))
![linear algebra - $\dim V<\infty$. Show there exists $m$ so that $\ker T^m \cap T^m(V)=0$ - Mathematics Stack Exchange linear algebra - $\dim V<\infty$. Show there exists $m$ so that $\ker T^m \cap T^m(V)=0$ - Mathematics Stack Exchange](https://i.stack.imgur.com/iLN7D.jpg)
linear algebra - $\dim V<\infty$. Show there exists $m$ so that $\ker T^m \cap T^m(V)=0$ - Mathematics Stack Exchange
Ingegneria dell'energia, A.A. 2019/20 ALGEBRA LINEARE F.Acquistapace, V.M.Tortorelli Settimo foglio di esercizi: lemma di Fitt
![linear algebra - Proving that $\dim T^{-1}(E) = \dim(\operatorname{Ker}T) + \dim (\operatorname{Ker}T\cap\operatorname{Im}(T))$ - Mathematics Stack Exchange linear algebra - Proving that $\dim T^{-1}(E) = \dim(\operatorname{Ker}T) + \dim (\operatorname{Ker}T\cap\operatorname{Im}(T))$ - Mathematics Stack Exchange](https://i.stack.imgur.com/CFR42.png)
linear algebra - Proving that $\dim T^{-1}(E) = \dim(\operatorname{Ker}T) + \dim (\operatorname{Ker}T\cap\operatorname{Im}(T))$ - Mathematics Stack Exchange
![Esercizi Settimana 5 - Esercitazione Algebra lineare e Geometria - Applicazioni Lineari Esercizi - Studocu Esercizi Settimana 5 - Esercitazione Algebra lineare e Geometria - Applicazioni Lineari Esercizi - Studocu](https://d20ohkaloyme4g.cloudfront.net/img/document_thumbnails/4e6b81df5bc2d3555abb4f14d0f2e2d8/thumb_1200_1697.png)
Esercizi Settimana 5 - Esercitazione Algebra lineare e Geometria - Applicazioni Lineari Esercizi - Studocu
![linear algebra - Finding dim(Ker(A)) according to a given characteristic polynomial - Mathematics Stack Exchange linear algebra - Finding dim(Ker(A)) according to a given characteristic polynomial - Mathematics Stack Exchange](https://i.stack.imgur.com/oX1Jw.png)
linear algebra - Finding dim(Ker(A)) according to a given characteristic polynomial - Mathematics Stack Exchange
![SOLVED: Suppose T: V -> V is a nilpotent linear operator with dim(V) = 15 and we know that dim(ker(T^1)) = 5 dim(ker(T^2)) = 9 dim(ker(T^3)) = 12 dim( ker(T^4)) = 14 dim(ker(T^5)) = SOLVED: Suppose T: V -> V is a nilpotent linear operator with dim(V) = 15 and we know that dim(ker(T^1)) = 5 dim(ker(T^2)) = 9 dim(ker(T^3)) = 12 dim( ker(T^4)) = 14 dim(ker(T^5)) =](https://cdn.numerade.com/ask_images/d92ab2b067c9476aa9963368192b40c6.jpg)